Question

How to find the second biggest number in a list with Scala

Answer 1

val list = List(3, 14, 4, 1, 5, 90, 2, 6, 85, 7)

val sortedNumbers = list.distinct.sorted

val secondLargest = sortedNumbers(sortedNumbers.length - 2)

println(s"The second largest number is $secondLargest")

  
  
/*
run:
    
The second largest number is 85

*/

 

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Answer 2

val list = List(3, 14, 4, 1, 5, 90, 2, 6, 85, 7)

val secondLargest = list.distinct.sorted(Ordering[Int].reverse).tail.head

println(s"The second largest number is $secondLargest")

  
  
/*
run:
    
The second largest number is 85

*/

 

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