Question

How to assign a value to a char* using hex format in C

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <string.h>

int main()
{
    int size = 32;
    
    char *ptr = malloc(sizeof(char) * size);
    memset(ptr, 0, size);
    
    // char *strncpy(char *dest, const char *src, size_t n)
    
    strncpy(ptr, "\x63\x20\x70\x72\x6F", size - 1);
    
    printf("%s\n", ptr);
    
    free(ptr);

    return 0;
}



/*
run:

c pro

*/

 

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