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How to set the width parameter in println! dynamically with a variable in Rust

2 Answers

0 votes
fn main() {
    let number: f64 = 283742.4397;
    let width = 10;
    let precision = 2;

    println!("{:width$.precision$}", number);
}



/*
run:
  
283742.44
  
*/

 



answered Nov 13, 2024 by avibootz
0 votes
fn main() {
    let number: f64 = 283742.4397;
    let width = 10;
    let precision = 2;

    println!("{:1$.2$}", number, width, precision);
}



/*
run:
  
283742.44
  
*/

 



answered Nov 13, 2024 by avibootz

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