Question

How to find a number in array that appears once in Kotlin

Answer 1

fun numberExistsFewTimes(arr: Array<Int>, number: Int, index: Int): Boolean {
    for (i in arr.indices) {
        if (arr[i] == number && i != index) {
            return true
        }
    }
    
    return false
}

fun getSingleNumber(arr: Array<Int>): Int {
    for (i in arr.indices) {
        if (!numberExistsFewTimes(arr, arr[i], i)) {
            return arr[i]
        }
    }
    
    return -1
}

fun main() {
    val arr = arrayOf(3, 2, 1, 2, 3, 3, 1, 5, 9, 7, 7, 9, 9)
    
    println(getSingleNumber(arr))
}



/*
run:
  
5
  
*/

 

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