Question

How to find the missing values in a sorted range (x to y) array with TypeScript

Answer 1

let x: number = 4;
let y: number = 17;
 
let arr: number[] = [5, 5, 5, 5, 6, 7, 9, 10, 10, 10, 11, 13];
 
let missingValues: Set<number> = new Set([...Array(y - x + 1).keys()].map(i => i + x)
                                                             .filter(i => !arr.includes(i)));
 
console.log("missingValues:", missingValues);
console.log("missingValues:", Array.from(missingValues));
  
  
  
/*
run:
  
"missingValues:",  Set (7) {4, 8, 12, 14, 15, 16, 17} 
"missingValues:",  [4, 8, 12, 14, 15, 16, 17] 

*/

 

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