Question

How to reverse an integer number in Swift

Answer 1

func ReverseIntegerNumber(number: inout Int) -> Int {
    var reverse = 0

    while (number != 0) {
       reverse = reverse * 10
       reverse = reverse + number % 10
       number = number / 10
    }
    
    return reverse
}

var num = 12345

print(ReverseIntegerNumber(number: &num))



/*
run:

54321

*/

 

70+ SQL courses for beginners and professionals