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How to count the number of non-overlapping instances of substring in a string in Scala

1 Answer

0 votes
import scala.util.matching.Regex

object Main extends App {
  val s = "scala java php c++ python php phphp"

  def count(s: String, substr: String): Int = {
    val pattern: Regex = (s"$substr").r
    pattern.findAllIn(s).length
  }

  println(count(s, "php"))
}


    
    
/*
run:
    
3
    
*/

 



answered Aug 24, 2024 by avibootz
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