How to create an array of numbers in Bash

1 Answer

0 votes
arr=(5 7 8 0 2 9)

for i in ${!arr[@]}; do
    echo "element $i is ${arr[$i]}"
done
 
 
 
# run:
#
# element 0 is 5
# element 1 is 7
# element 2 is 8
# element 3 is 0
# element 4 is 2
# element 5 is 9
#

 



answered Aug 9, 2024 by avibootz

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