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How to print a number as binary, octal and hexadecimal in Rust

1 Answer

0 votes
fn main() {
    let n = 8392;
    
    println!("Base 10:               {}",   n); 
    println!("Base 2 (binary):       {:b}", n); 
    println!("Base 8 (octal):        {:o}", n); 
    println!("Base 16 (hexadecimal): {:x}", n); 
}

   
   
/*
run:

Base 10:               8392
Base 2 (binary):       10000011001000
Base 8 (octal):        20310
Base 16 (hexadecimal): 20c8

*/

 



answered Aug 8, 2024 by avibootz

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