Question

How to escape the % (percent) sign in printf with C

Answer 1

#include <stdio.h>

int main(void) {
    int discount = 10;
    char ch = '%';
    
    printf("discount = %d%c\n", discount, ch);

    return 0;
}
  
   
   
/*
run:
  
discount = 10%
   
*/

 

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Answer 2

#include <stdio.h>

int main(void) {
    int discount = 10;

    printf("discount = %d%%\n", discount);

    return 0;
}
  
   
   
/*
run:
  
discount = 10%
   
*/

 

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