Question

How to pass the address of a pointer to a function in C

Answer 1

#include <stdio.h>

void changeValue(int **p) {
    **p = 700;
}
    
int main()
{
    int n = 15;
    int *p = &n;
    
    printf("%d %d\n", *p, n);
    
    changeValue(&p);
    
    printf("%d %d\n", *p, n);
}



/*
run:

15 15
700 700

*/

 

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