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How to generate all unique 2-digit permutations from a given 3-digit number in JavaScript

1 Answer

0 votes
const generate_2_digit_permutations_from_3_digit_number = (threeDigitNumber) => {
    const twoDigitPermutations = new Set();

    // Generate all two_digit_permutations of three_digit_number
    for (let i = 0; i < threeDigitNumber.length; i++) {
        for (let j = 0; j < threeDigitNumber.length; j++) {
            if (i !== j) {
                twoDigitPermutations.add(`${threeDigitNumber[i]}${threeDigitNumber[j]}`);
            }
        }
    }

    return twoDigitPermutations;
};

const threeDigitNumber = '185';

const twoDigitPermutations = generate_2_digit_permutations_from_3_digit_number(threeDigitNumber);

console.log(twoDigitPermutations);

 
 
 
/*
run:
 
Set(6) { '18', '15', '81', '85', '51', '58' }
 
*/


 



answered Jun 16, 2024 by avibootz
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