How to get the current source file name and line number in VB.NET

1 Answer

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Imports System
Imports System.Runtime.CompilerServices

Public Class Program
    Public Shared Sub Log(<CallerFilePath> ByVal Optional filePath As String = "",
						  <CallerLineNumber> ByVal Optional lineNumber As Integer = 0)
        
		Console.WriteLine("filePath: " & filePath)
        Console.WriteLine("lineNumber: " & lineNumber)
    End Sub

    Public Shared Sub Main()
        Log()
    End Sub
End Class
 
   
   
' run:
'
' filePath: D:\Windows\TEMP\example.vb
' lineNumber: 13
'

 



answered Jun 11, 2024 by avibootz

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