How to convert a list of digits to an integer add 1 and convert it back to a list of digits in Python

1 Answer

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import math

def convert_array_of_digits_to_int_number(lst):
    n = 0
    for digit in lst:
        n = n * 10 + digit
    return n

def convert_int_number_to_array_of_digits(digits, n):
    i = len(digits) - 1
    while n > 0:
        digits[i] = n % 10
        n //= 10
        i -= 1

lst = [9, 4, 6, 9]
n = convert_array_of_digits_to_int_number(lst)

n += 1

convert_int_number_to_array_of_digits(lst, n)

print(f"n = {n}")
print(lst)



'''
run:
  
n = 9470
[9, 4, 7, 0]

'''

 



answered May 7, 2024 by avibootz
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