How to initialize an array of bytes with hex values in Java

1 Answer

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import java.util.Arrays;

public class MyClass {
    public static void main(String args[]) { 
        byte[] arr = {0x4a, 0x61, 0x76, 0x61};
         
        for (byte ch : arr) {
            System.out.print((char)ch);
        }
        
        System.out.println();
        
        System.out.println(Arrays.toString(arr));
    }
}
 
 
 
/*
run:
 
Java
[74, 97, 118, 97]
 
*/

 



answered Apr 10, 2024 by avibootz

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