Question

How to check if second string a rotated version of first string in TypeScript

Answer 1

const secondStringRotatedOfFirstString = (first: string, second: string) => {
    if (first.length !== second.length){
        return false
    };

    for (let i: number = 0; i < first.length; i++) {
        const rotated = first.slice(i).concat(first.slice(0, i));
        if (rotated === second) {
            return true
        };
    }
    
    return false;
};

const first: string = 'abcdefg';  
const second: string = 'cdefgab';

console.log(secondStringRotatedOfFirstString(first, second));




/*
run:

true

*/

 

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