Question

How to find the count of all different digits in a number in C

Answer 1

#include <stdio.h>

static int count[10] = {0}; 
 
void count_of_all_different_digits(long int n) {
    char buf[64];
    sprintf(buf, "%ld", n);

    for (int i = 0; buf[i] != '\0'; i++) {
        count[buf[i] - '0']++;
    }
}
  
int main() {
    count_of_all_different_digits(918332788406);
    
    for (int i = 0; i < 10; i++) {
        if (count[i] >= 1) {
            printf("%d: %d\n", i, count[i]);
        }
    }
      
    return 0;
}
  
  
  
/*
run:
  
1: 1
2: 1
3: 2
4: 1
6: 1
7: 1
8: 3
9: 1
  
*/

 

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