How to create an ASCII array that represents each character of a string in C

1 Answer

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#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int* createASCIIArray(char str[], int length) {
    int* arr = malloc(length * sizeof(int));
     
    for (int i = 0; i < length; i++) {
        arr[i] = (int)str[i];
    }
     
    return arr;
}
 
int main() {
    char str[] = "C programming";
    int length = strlen(str);
    
    int* arr = createASCIIArray(str, length);
    
    for (int i = 0; i < length; i++) {
        printf("%d ", arr[i]);
    }

    free(arr);
     
    return 0;
}
 
 
 
 
/*
run:

67 32 112 114 111 103 114 97 109 109 105 110 103 
    
*/

 



answered Mar 4, 2024 by avibootz
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