Welcome to collectivesolver - Programming & Software Q&A with code examples. A website with trusted programming answers. All programs are tested and work.

Contact: aviboots(AT)netvision.net.il

Buy a domain name - Register cheap domain names from $0.99 - Namecheap

Scalable Hosting That Grows With You

Secure & Reliable Web Hosting, Free Domain, Free SSL, 1-Click WordPress Install, Expert 24/7 Support

Semrush - keyword research tool

Boost your online presence with premium web hosting and servers

Disclosure: My content contains affiliate links.

39,890 questions

51,821 answers

573 users

How to check if a list of Integers is sorted in Java

2 Answers

0 votes
import java.util.Arrays;
import java.util.List;
 
public class Program {
    public static boolean listIsSorted(List<Integer> list) {
        int size = list.size();
         
        for (int i = 0; i < size - 1; i++) {
            if (list.get(i) >= list.get(i + 1)) {
                return false;
            }
        }
         
        return true;
    }
     
    public static void main(String[] args) {
        List<Integer> list = Arrays.asList(3, 5, 6, 9, 12, 34, 567, 890);
 
        System.out.println(listIsSorted(list));
    }
}
 
 
 
/*
run:
 
true
 
*/

 



answered Feb 26, 2024 by avibootz
edited Feb 26, 2024 by avibootz
0 votes
import java.util.List;
import java.util.Arrays;
import java.util.stream.Collectors;
 
public class Program {
    public static void main(String[] args) {
        List<Integer> list = Arrays.asList(3, 5, 6, 9, 12, 34, 567, 890);
        
        boolean result = list.stream().sorted().collect(Collectors.toList()).equals(list);
 
        System.out.println(result);
    }
}
 
 
 
/*
run:
 
true
 
*/

 



answered Feb 26, 2024 by avibootz

Related questions

...