How to remove digits from left to right from a number one by one until the number remain one digit in C++

1 Answer

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#include <iostream>
#include <cmath>
  
int truncate_left(int num) {
    int total = (int)log10(num); // total - 1 = 3
      
    int first_digit = num / pow(10, (total));
      
    return num - first_digit * pow(10, (total));
}
   
int main(void) {
    int num = 74853;
           
    while (num > 9) {
        num = truncate_left(num);
        std::cout << num << "\n";
    }
}
   
   
   
   
/*
run:
       
4853
853
53
3
       
*/

 

 



answered Jan 15, 2024 by avibootz
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