Question

How to truncate a number from left in VB.NET

Answer 1

Imports System

Public Class Program
	Public Shared Function truncate_left(ByVal num As Integer) As Integer
        Dim total As Integer = CInt(Math.Log10(num)) - 1 ' // total - 1 = 3
        Dim first_digit As Integer = num \ CInt(Math.Pow(10, (total)))
		
        Return num - first_digit * CInt(Math.Pow(10, (total)))
    End Function

    Public Shared Sub Main(ByVal args As String())
        Dim num As Integer = 7483
		
        Console.Write(truncate_left(num))
    End Sub
End Class



' run:
'
' 483
'

 

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