How to check whether a numbers are palindrome in base 10 and base 2 with C++

1 Answer

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#include <algorithm>
#include <iostream>
#include <bitset>
  
bool isBinaryRepresentationOfNumberPalindrome(unsigned int num) {
    std::string binary = std::bitset<16>(num).to_string(); 
    binary.erase(0, binary.find_first_not_of('0'));

    std::string reversebinary = binary;
    std::reverse(reversebinary.begin(), reversebinary.end());
   
    return binary == reversebinary;
}

bool isPalindrome(int n) {
    int reverse = 0, temp = n;
 
    while (temp != 0) {
        int remainder = temp % 10;
        reverse = (reverse * 10) + remainder;
        temp = temp / 10;
    }
 
    return n == reverse;
}
  
int main()
{
    unsigned int n = 585; // 1001001001
 
    std::cout << (isPalindrome(n) && isBinaryRepresentationOfNumberPalindrome(n) ? "yes" : "no");
}
  
    
    
    
/*
run:
    
yes
    
*/

 



answered Jan 8, 2024 by avibootz
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