Question

How to find min and max of three (3) int numbers in C

Answer 1

#include <stdio.h> 

int min(int a, int b);
int max(int a, int b);

int main(void)
{
    printf("max = %i\n", max(max(3, 7), 9)); // max = 9
    printf("max = %i\n", max(max(20, 8), 30)); // max = 30
    printf("max = %i\n", max(max(50, 8), 30)); // max = 50
    
    printf("min = %i\n", min(min(4, 9), 3)); // min = 3
    printf("min = %i\n", min(min(40, 13), 5)); // min = 5
    printf("min = %i\n", min(min(2, 13), 5)); // min = 2
    
    return 0;
}

int max(int a, int b)
{
    int t = a;
        
    if (b > t) t = b;
 
    return t;
}
 
int min(int a, int b)
{
    int t = a;
        
    if (b < t) t = b;
 
    return t;
}   

/*
run:
  
max = 9
max = 30
max = 50
min = 3
min = 5
min = 2

*/
 

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Answer 2

#include <stdio.h>
 
#ifndef max
    #define max(a, b) ( ((a) > (b)) ? (a) : (b) )
#endif
 
#ifndef min
    #define min(a, b) ( ((a) < (b)) ? (a) : (b) )
#endif
 
int main(void)
{
    printf("max = %i\n", max(max(3, 7), 9)); // max = 9
    printf("max = %i\n", max(max(20, 8), 30)); // max = 30
    printf("max = %i\n", max(max(50, 8), 30)); // max = 50
     
    printf("min = %i\n", min(min(4, 9), 3)); // min = 3
    printf("min = %i\n", min(min(40, 13), 5)); // min = 5
    printf("min = %i\n", min(min(2, 13), 5)); // min = 2
     
    return 0;
}

/*
run:
   
max = 9
max = 30
max = 50
min = 3
min = 5
min = 2
 
*/
 

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Answer 3

#include <stdio.h> 
 
int min(int a, int b);
int max(int a, int b);
 
int main(void)
{
    printf("max = %i\n", max(max(3, 7), 9)); // max = 9
    printf("max = %i\n", max(max(20, 8), 30)); // max = 30
    printf("max = %i\n", max(max(50, 8), 30)); // max = 50
     
    printf("min = %i\n", min(min(4, 9), 3)); // min = 3
    printf("min = %i\n", min(min(40, 13), 5)); // min = 5
    printf("min = %i\n", min(min(2, 13), 5)); // min = 2
     
    return 0;
}
  
int max(int a, int b)
{
    return (a > b) ? a : b;
}
 
int min(int a, int b)
{
   return (a < b) ? a : b;
}   
 
/*
run:
  
max = 9
max = 30
max = 50
min = 3
min = 5
min = 2

*/

 

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