How to print the bits that need to be flipped to convert a number to another number in C

1 Answer

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#include <stdio.h>
 
void printNeedToBeFlippedBits(int num1, int num2) {
    int bitNum = 0;
    int lsb1 = 0, lsb2 = 0;
 
    while ((num1 > 0) || (num2 > 0)) {
        lsb1 = num1 & 1;
        lsb2 = num2 & 1;
 
        if (lsb1 != lsb2) {
            printf("%d ", bitNum);
        }
 
        num1 = num1 >> 1;
        num2 = num2 >> 1;
        
        bitNum++;
    }
}
 
int main()
{
    int num1 = 2;  // 00000010
    int num2 = 17; // 00010001
    printNeedToBeFlippedBits(num1, num2);
    
    printf("\n");
    
    num1 = 3;   // 00000011
    num2 = 221; // 11011101
    printNeedToBeFlippedBits(num1, num2);
     
    return 0;
}
 
 
   
   
/*
run:
 
0 1 4 
1 2 3 4 6 7 
     
*/

 



answered Dec 25, 2023 by avibootz
edited Dec 25, 2023 by avibootz
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