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How to check if a number is evil number (binary representation contains even number of 1) in VB.NET

1 Answer

0 votes
' Evil number = positive whole number whose binary representation contains an even number of 1's

Imports System

Public Class Program
    Public Shared Function countNumberOfOne(ByVal binaryNumber As String) As Integer
        Dim length As Integer = binaryNumber.Length
        Dim count As Integer = 0
        Dim ch As Char

        For i As Integer = 0 To length - 1
            ch = binaryNumber(i)
            If ch = "1"c Then
                count += 1
            End If
        Next

        Return count
    End Function

    Public Shared Function checkEvilNumber(ByVal number As Integer) As Boolean
        Dim binaryNumber As String = Convert.ToString(number, 2)
	
        Console.Write(number & " = " & binaryNumber & " = ")
	
        Return If ((countNumberOfOne(binaryNumber) Mod 2 = 0), True, False)
    End Function

    Public Shared Sub Main(ByVal args As String())
        Dim number As Integer = 23
		
        Console.WriteLine(checkEvilNumber(number))
        
		number = 9863
		
        Console.WriteLine(checkEvilNumber(number))
    End Sub
End Class



' run:
'
' 23 = 10111 = True
' 9863 = 10011010000111 = False
'

 



answered Nov 25, 2023 by avibootz
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