Question

How to calculate the sum of digits of 2 power 15 in C++

Answer 1

#include <iostream>
#include <cmath>

int sumDigits(long num) {
    int sum = 0;
    while (num != 0) {
        sum += num % 10;
        num /= 10;
    }
      
    return sum;
}

int main() {
    int base = 2;
    int exponent = 15;
   
    long power = (long)pow(base, exponent); // 32768

    std::cout << sumDigits(power);
}
 
 
 
 
/*
run:
 
26

*/

 

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