Question

How to catch multiple exceptions in the same catch clause with Java

Answer 1

public class MyClass {
    public static void main(String args[]) {
        try {
            int[] arr = {1, 2, 3, 4, 5, 6, 7};
               
            arr[19] = 938;
           
        } catch (ArrayIndexOutOfBoundsException | ArithmeticException e) {
            System.out.println("Exception: " + e);
        }
    }
}
 
 
 
 
/*
run:

Exception: java.lang.ArrayIndexOutOfBoundsException: Index 19 out of bounds for length 7

*/

 

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Answer 2

public class MyClass {
    public static void main(String args[]) {
        try {
            int[] arr = {1, 2, 3, 4, 5, 6, 7};
               
            arr[19] = 938;
           
        } catch (ArrayIndexOutOfBoundsException e) {
            System.out.println("Exception 1: " + e);
        } catch (ArithmeticException e) {
            System.out.println("Exception 2: " + e);
        }
    }
}
 
 
 
 
/*
run:

Exception 1: java.lang.ArrayIndexOutOfBoundsException: Index 19 out of bounds for length 7

*/

 

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