Question

How to find pythagorean triplet for which a + b + c = 25 in C++

Answer 1

#include <iostream>

int main()
{
    const int sum = 25;
     
    for (int a = 1; a <= sum / 3; a++) {
        for (int b = a + 1; b <= sum / 2; b++) {
            for (int c = b + 1; c <= sum; c++) {
                if (a * a + b * b == c * c && a * a + b * b == 25) {
                    std::cout << "a = " << a << " b = " << b << " c = " << c;
                }
            }
        }
    }
}
 
  
// (3 ^ 2 = 9) + (4 ^ 2 = 16) = 25 = 5 ^ 2
 
 
  
/*
run:
  
a = 3, b = 4, c = 5
  
*/

 

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