How to rearrange an array such that every second element becomes greater than its left and right element with C#

1 Answer

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using System;

public class Program
{
	private static void swap(int[] arr, int i, int j) {
		int temp = arr[i];
		arr[i] = arr[j];
		arr[j] = temp;
	}

	private static void rearrangeArray(int[] arr) {
		int size = arr.Length;

		for (int i = 1; i < size; i += 2) {
			// previous element is greater than current element
			if (arr[i - 1] > arr[i]) {
				swap(arr, i - 1, i);
			}

			//  next element is greater than current element
			if (i + 1 < size && arr[i + 1] > arr[i]) {
				swap(arr, i + 1, i);
			}
		}
	}
	public static void Main(string[] args)
	{
		int[] arr = new int[] {1, 3, 6, 5, 4, 2, 9, 8, 7};

		rearrangeArray(arr);

		Console.WriteLine(string.Join(" ", arr));
	}
}






/*
run:
  
1 6 3 5 2 9 4 8 7
  
*/

 



answered Sep 30, 2023 by avibootz
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