How to rearrange an array such that every second element becomes greater than its left and right element with Java

1 Answer

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import java.util.Arrays;

public class MyClass {
    private static void swap(int[] arr, int i, int j) {
    	int temp = arr[i];
    	arr[i] = arr[j];
    	arr[j] = temp;
    }

    private static void rearrangeArray(int[] arr) {
        int size = arr.length;

    	for (int i = 1; i < size; i += 2) {
    		// previous element is greater than current element
    		if (arr[i - 1] > arr[i]) {
    			swap(arr, i - 1, i);
    		}
    
    		//  next element is greater than current element
    		if (i + 1 < size && arr[i + 1] > arr[i]) {
    			swap(arr, i + 1, i);
    		}
    	}
    }
    public static void main(String args[]) {
      	int[] arr = {1, 3, 6, 5, 4, 2, 9, 8, 7};

	    rearrangeArray(arr);

	    System.out.println(Arrays.toString(arr));
    }
}






/*
run:
 
[1, 6, 3, 5, 2, 9, 4, 8, 7]
 
*/

 



answered Sep 30, 2023 by avibootz
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