Question

How to exit a program with an error code in PHP

Answer 1

$a = 100;
$b = 0;
if ($b == 0)
    exit(1);
else
    echo $a/$b;


/*
run: 



*/

 

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Answer 2

$a = 100;
$b = 0;
if ($b == 0)
    exit('$b is 0');
else
    echo $a/$b;


/*
run: 

$b is 0

*/

 

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