Question

How to count the numbers with even number of digits in an array with C++

Answer 1

#include <iostream>
#include <cmath>
 
int count_even_numbers(int arr[], int size) {
    int result = 0;
 
    for (int i = 0; i < size; i++) {
        int total_digits = (log10(arr[i]) + 1);
         
        if (total_digits % 2 == 0)
            result++;
    }
             
    return result;
}
 
int main()
{
    int array[] = {564, 90, 7, 1248, 47325, 834921, 1234567};
     
    int size = sizeof(array) / sizeof(array[0]);
     
    std::cout << count_even_numbers(array, size);
}
 
 
 
 
/*
run:
 
3
 
*/

 

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