Question

How to sort 2D array (matrix) by first column value in TypeScript

Answer 1

function compareFirstColumn(a: any, b: any) {
    if (a[0] === b[0]) {
        return 0;
    }
    else {
        return (a[0] < b[0]) ? -1 : 1;
    }
}

const matrix: any[][] = [[41, 'java', 'a'], 
                         [15, 'typecript', 'z'], 
                         [3, 'c', 'x'], 
                         [20, 'c++', 'q']];

matrix.sort(compareFirstColumn);

console.log(matrix);




/*
run:

[[3, "c", "x"], [15, "typecript", "z"], [20, "c++", "q"], [41, "java", "a"]] 

*/

 

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Answer 2

const matrix: any[][] = [[41, 'java', 'a'], 
                         [15, 'typecript', 'z'], 
                         [3, 'c', 'x'], 
                         [20, 'c++', 'q']];

matrix.sort(function(a: any[], b: any[]) {
    return a[0] - b[0]
});

console.log(matrix);




/*
run:

[[3, "c", "x"], [15, "typecript", "z"], [20, "c++", "q"], [41, "java", "a"]] 

*/

 

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