Question

How to check if a given row is sorted in a matrix with TypeScript

Answer 1

function isRowSorted(matrix: number[][], row: number) {
    const cols: number = matrix[0].length;
    
    for (let i: number = 0; i < cols; i++) {
        if (matrix[row][i - 1] > matrix[row][i]) {
            return false;
        }
    }
    return true;
}

const matrix: number[][] = [[ 4,  7,  9, 12], 
                            [ 1,  8,  3,  4], 
                            [-9, -4, -3,  2], 
                            [-8, -3, -9,  4], 
                            [ 2,  6,  7, 18]];
        
console.log("Row 0: " + isRowSorted(matrix, 0));
console.log("Row 1: " + isRowSorted(matrix, 1));
console.log("Row 2: " + isRowSorted(matrix, 2));
console.log("Row 3: " + isRowSorted(matrix, 3));
console.log("Row 4: " + isRowSorted(matrix, 4));




/*
run:

"Row 0: true" 
"Row 1: false" 
"Row 2: true" 
"Row 3: false" 
"Row 4: true" 

*/

 

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