How to initialize array with zeros and multiple numbers at specific indexes with C

1 Answer

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#include <stdio.h>

int main(void)
{
    int arr[14] = { 1, 3, 2, 7, [8] = 18, 19, 20 };

    int size = sizeof(arr) / sizeof(arr[0]);

    for (int i = 0; i < size; i++)
        printf("%3d", arr[i]);

    return 0;
}



/*
run:

  1  3  2  7  0  0  0  0 18 19 20  0  0  0

*/

 



answered Apr 24, 2023 by avibootz
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