Question

How to check if a number is cyclops (number with odd number of digits and zero in the center) in C++

Answer 1

#include <iostream>

bool isCyclopsNumber(int n) {
    if (n == 0) {
        return true;
    }
    
    int m = n % 10;
    int count = 0;
    while (m != 0) {
        count++;
        n /= 10;
        m = n % 10;
    }
    
    n /= 10;
    m = n % 10;
    while (m != 0) {
        count--;
        n /= 10;
        m = n % 10;
    }
    
    return n == 0 && count == 0;
}

int main(void) {

    std::cout << (isCyclopsNumber(209) ? "yes" : "no") << "\n";
    std::cout << (isCyclopsNumber(18037) ? "yes" : "no") << "\n";
    std::cout << (isCyclopsNumber(5604) ? "yes" : "no") << "\n";
}




/*
run:

yes
yes
no

*/

 

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Answer 2

#include <iostream>
#include <sstream>

bool OnlyOneZero(std::string str) {
    int count = 0;
    
    for (char ch : str) {
        if (ch == '0') {
            count++;
        }
    }
    
    return count == 1;
}
 
bool isCyclopsNumber(int n) {
    if (n == 0) {
        return true;
    }
     
    std::stringstream stream;
    stream << n;
 
    std::string str;
    stream >> str;
 
    if (!(str.length() % 2)) {
        return false;
    }
 
    if (!OnlyOneZero(str)) {
        return false;
    }
 
    int mid_index = str.length() / 2;
    if (str[mid_index] == '0')
        return true;
 
    return false;
}
 
int main(void) {
 
    std::cout << (isCyclopsNumber(209) ? "yes" : "no") << "\n";
    std::cout << (isCyclopsNumber(18037) ? "yes" : "no") << "\n";
    std::cout << (isCyclopsNumber(5604) ? "yes" : "no") << "\n";
}
 
 
 
 
 
/*
run:
 
yes
yes
no
 
*/

 

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