Question

How to sort a list in ascending order in Java

Answer 1

import java.util.List;
import java.util.Arrays;
import java.util.Comparator;
 
public class MyClass 
{
    public static void main(String[] args)
    {
        List<Integer> list = Arrays.asList(2, 5, 1, 9, 0, 4, 7);
 
        list.sort(Comparator.naturalOrder());
        
        System.out.println(list);
    }
}
 
 

 
/*
run:
 
[0, 1, 2, 4, 5, 7, 9]
 
*/

 

 

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Answer 2

import java.util.List;
import java.util.Arrays;
import java.util.Collections;
 
public class MyClass 
{
    public static void main(String[] args)
    {
        List<Integer> list = Arrays.asList(2, 5, 1, 9, 0, 4, 7);
 
        Collections.sort(list);
        
        System.out.println(list);
    }
}
 
 

 
/*
run:
 
[0, 1, 2, 4, 5, 7, 9]
 
*/

 

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Answer 3

import java.util.List;
import java.util.Arrays;
import java.util.stream.Collectors;
 
public class MyClass 
{
    public static void main(String[] args)
    {
        List<Integer> list = Arrays.asList(2, 5, 1, 9, 0, 4, 7);
 
        list = list.stream()
                    .sorted()
                    .collect(Collectors.toList());
        
        System.out.println(list);
    }
}
 
 

 
/*
run:
 
[0, 1, 2, 4, 5, 7, 9]
 
*/

 

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