Question

How to reshaping a matrix (2D array) using fortran-like index ordering with NumPy in Python

Answer 1

# Fortran order = All elements of an array are stored in column-major order

import numpy as np

arr = np.arange(12).reshape((3, 4))
print(arr)

print()

arr = np.reshape(arr, (4, 3), order='F')
print(arr)




'''
run:

[[ 0  1  2  3]
 [ 4  5  6  7]
 [ 8  9 10 11]]

[[ 0  5 10]
 [ 4  9  3]
 [ 8  2  7]
 [ 1  6 11]]

'''

 

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