How to rotate a number to the right by N bits using bit operation in C

1 Answer

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#include <stdio.h>

void print_bits(int n, int size) {
	for (int i = 1 << (size - 1); i > 0; i = i / 2)
		(n & i) ? printf("1") : printf("0");
}

unsigned int rotate_right(unsigned int num, unsigned int n) {
	return (num >> n) | (num << (32 - n));
}

int main(void)
{
	int num = 16;

	print_bits(num, 8);
	printf("\n");

	num = rotate_right(num, 2);

	print_bits(num, 8);
	printf("\n");

	printf("%d", num);

	return 0;
}




/*
run:
 
00010000
00000100
4
 
*/

 



answered Jan 9, 2023 by avibootz
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