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How to shuffle an array in C

1 Answer

0 votes
#include <stdio.h>
#include <stdlib.h>
#include <time.h>

void swap(int arr[], int i, int j) {
	int temp = arr[i];
	arr[i] = arr[j];
	arr[j] = temp;
}

void shuffle(int arr[], int n) {
	for (int i = n - 1; i >= 1; i--) {
		int j = rand() % (i + 1);
		swap(arr, i, j);
	}
}

int main() {
	int arr[] = { 1, 2, 3, 4, 5, 6, 7, 8, 9, 0 };
	int len = sizeof(arr) / sizeof(arr[0]);

	srand((unsigned int)time(NULL));

	shuffle(arr, len);

	for (int i = 0; i < len; i++) {
		printf("%d ", arr[i]);
	}

	return 0;
}




/*
run:
     
5 8 1 6 9 7 2 0 3 4
  
*/

 



answered Jan 4, 2023 by avibootz

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