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How to print array of numbers in Rust

3 Answers

0 votes
fn main() {
    let numbers: &[i32] = &[4, 5, 8, 0, 1];
    
    for n in numbers {
        println!("{}", n);
    }
}




/*
run:

4
5
8
0
1

*/

 





answered Dec 9, 2022 by avibootz
0 votes
fn main() {
    let numbers = [4, 5, 8, 0, 1];
    
    for n in numbers {
        println!("{}", n);
    }
}




/*
run:

4
5
8
0
1

*/

 





answered Dec 9, 2022 by avibootz
0 votes
fn main() {
    let numbers:[i32; 5] = [4, 5, 8, 0, 1];
    
    for n in numbers {
        println!("{}", n);
    }
}




/*
run:

4
5
8
0
1

*/

 





answered Dec 9, 2022 by avibootz

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