How to check if a matrix is an identity matrix (1 on the main diagonal and 0 elsewhere) in TypeScript

1 Answer

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function is_identity_matrix(mtrix : number[][]) {
    const rows : number = mtrix.length;
    const cols : number = mtrix[0].length;
 
  for (let i : number = 0; i < rows; i++) {
    for (let j : number = 0; j < cols; j++) {
        if (i == j && mtrix[i][j] != 1) {  
            return false;  
        }  
        if (i != j && mtrix[i][j] != 0) {  
          return false;   
        }  
    }
  }
  return true;
}
 
const mtrix : number[][] = 
     [  [1, 0, 0],  
        [0, 1, 0],  
        [0, 0, 1] ];
 
console.log(is_identity_matrix(mtrix));
   
     

     
/*
run:
     
true
     
*/

 



answered Nov 20, 2022 by avibootz
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