Question

How to sum the proper divisors of a number in PHP

Answer 1

function SumNumberProperDivisors($num) {
    $sum = 0;
   
    for ($i = 1; $i <= $num / 2; $i++) {
        if ($num % $i == 0) {
            $sum += $i;
            echo $i . ", ";
        }
    }
   
    return $sum;
}
   
echo "\n". SumNumberProperDivisors(220);
  
  
  
 
/*
run:
  
1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110, 
284
  
*/

 

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