Question

How to sum the proper divisors of a number in C#

Answer 1

using System;
 
public class MyClass
{
    private static int SumNumberProperDivisors(int num) {
        int sum = 0;
 
        for (int i = 1; i <= num / 2; i++) {
            if (num % i == 0) {
                Console.Write("{0:D}, ", i);
                sum += i;
            }
        }
        return sum;
    }
    public static void Main(string[] args)
    {
        int sum = SumNumberProperDivisors(220);
 
        Console.WriteLine();
        Console.Write(sum);
    }
}
 
 
 
 
 
 
/*
run:
   
1, 2, 4, 5, 10, 11, 20, 22, 44, 55, 110, 
284
   
*/

 

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