Question

How to calculate the average of a double array of given length in C++

Answer 1

#include <iostream>

double average(double *arr, int len) {
	double sum = 0;

	for (int i = 0; i < len; i++)
		sum += arr[i];

	return sum / len;
}

int main()
{
	double arr[] = {3.14, 8.0, 2.87, 5.982, 10.0};
	int len = sizeof arr/sizeof arr[0];
	
	for (; len >= 0; len--) {
		std::cout << "average[";
		for (int i = 0; i < len; i++)
			std::cout << (i ? ", " : "") << arr[i];

		std::cout << "] = " << average(arr, len) << "\n";
		
		
	}
}




/*
run:

average[3.14, 8, 2.87, 5.982, 10] = 5.9984
average[3.14, 8, 2.87, 5.982] = 4.998
average[3.14, 8, 2.87] = 4.67
average[3.14, 8] = 5.57
average[3.14] = 3.14
average[] = -nan

*/

 

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