How to replace every element in array by multiplication of next and previous elements with VB.NET

1 Answer

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' arr(first) = arr(first) (itself) * arr(next);
' arr(last) = prev * arr(last) (itself);

Imports System

Public Class Program
    Public Shared Sub MultiplyNextPrevious(ByVal arr As Integer())
        Dim size As Integer = arr.Length

        If size <= 1 Then
            Return
        End If

        Dim prev As Integer = arr(0)
        arr(0) = arr(0) * arr(1)

        For i As Integer = 1 To size - 1 - 1
            Dim curr As Integer = arr(i)
            arr(i) = prev * arr(i + 1)
            prev = curr
        Next

        arr(size - 1) = prev * arr(size - 1)
    End Sub

    Public Shared Sub Main(ByVal args As String())
        Dim arr As Integer() = New Integer() {2, 3, 5, 6, 12, 8, 10, 7}
	
        MultiplyNextPrevious(arr)

        For i As Integer = 0 To arr.Length - 1
            Console.Write(arr(i) & " ")
        Next
    End Sub
End Class




' run:
'
' 6 10 18 60 48 120 56 70
'

 



answered Oct 2, 2022 by avibootz
edited Oct 2, 2022 by avibootz
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