Question

How to count the characters need to be removed so that two strings become anagram in C

Answer 1

#include <stdio.h>
#include <math.h>

#define TOTAL_ABC_LETTERS 26

int CountCharactersNeedToBeRemovedForAnagram(char str1[], char str2[]) {
    int count1[TOTAL_ABC_LETTERS] = { 0 }, count2[TOTAL_ABC_LETTERS] = { 0 };

    // count char frequency str1
    for (int i = 0; str1[i] != '\0'; i++)
        count1[str1[i] - 'a']++;

    // count char frequency str2
    for (int i = 0; str2[i] != '\0'; i++)
        count2[str2[i] - 'a']++;

    int result = 0;
    for (int i = 0; i < TOTAL_ABC_LETTERS; i++)
        result += abs(count1[i] - count2[i]);

    return result;
}

int main()
{
    char str1[] = "masterfx", str2[] = "ksampret";

    printf("%d\n", CountCharactersNeedToBeRemovedForAnagram(str1, str2));
}




/*
run:

4

*/

 

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