Question

How to find the combination of three elements in an array whose sum is equal to N in C++

Answer 1

#include <iostream>

void PrintThreeElements(int arr[], int size, int N) {
    for (int i = 0; i < size; i++) {
        for (int j = i + 1; j < size; j++) {
            for (int k = j + 1 ; k < size; k++) {
                if (arr[i] + arr[j] + arr[k] == N) {
                   std::cout << arr[i] << " " << arr[j] << " " << arr[k];
                   return;
                }
            }
        }
    }
}

int main()
{
    int arr[] = {3, 2, 6, 4, 10, 5, 9, 7, 8, 12};
    int N = 24;
    int size = sizeof(arr)/sizeof(arr[0]); 

    PrintThreeElements(arr, size, N);
}




/*
run:

3 9 12

*/

 

70+ SQL courses for beginners and professionals