Question

How to find the second most frequent character in a string with JavaScript

Answer 1

function GetSecondMostFrequentChar(s) {
    let count = Array(256).fill(0);  // 256 = ASCII table size
        
    for (let i = 0; i < s.length; i++) {
        count[s.charAt(i).charCodeAt(0)]++;
    }
        
    let first = 0;
    let second = 0;
        
    for (let i = 0; i < 256; i++) {
        if (count[i] > count[first]) {
            second = first;
            first = i;
        }
        else if (count[i] > count[second] && count[i] != count[first]) {
                second = i;
            }
        }
    
    return String.fromCharCode(second);
}

const str = "bbaddddccce";
        
console.log(GetSecondMostFrequentChar(str));





/*
run:

"c"

*/

 

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