Question

How to find the second most frequent character in a string with Java

Answer 1

public class MyClass {
    public static char GetSecondMostFrequentChar(String s) {
	    int[] count = new int[256]; // 256 = ASCII table size

	    for (int i = 0; i < s.length(); i++) {
		    count[s.charAt(i)]++;
	    }

	    int first = 0;
	    int second = 0;

	    for (int i = 0; i < 256; i++) {
		    if (count[i] > count[first]) {
			    second = first;
			    first = i;
		    }
		    else if (count[i] > count[second] && count[i] != count[first]) {
				    second = i;
		        }
	    }

	    return (char)second;
    }

    public static void main(String args[]) {
        String str = "bbaddddccce";

	    System.out.print(GetSecondMostFrequentChar(str));
    }
}




/*
run:
   
c
   
*/

 

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